AIIMS 2019 Physics Isobaric Processes MCQ Question

In an isobaric process, the heat added to a gas can be calculated using the formula $Q = W + \Delta U$, where $Q$ is the heat added, $W$ is the work done by the gas, and $\Delta U$ is the change in internal energy. For a diatomic gas, the change in internal energy can be expressed as $\Delta U = \frac{5}{2} n R \Delta T$. Given that the work done $W$ is 10 J, and assuming the internal energy change is negligible or accounted for in the options, the heat added $Q$ is determined to be 35 J, making option A correct. Other options are incorrect as they do not satisfy the energy balance in the context of an isobaric process with the given work done.