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AIIMS2019Physics-Thermodynamics

AIIMS 2019 Physics Radiation MCQ Question

Type: MCQ-conceptual-Hard-Class 11

Distance between sun and Earth is 2×10⁸ km, temperature of sun 6000 K, radius of sun 7×10⁵ km. If emissivity of the earth is 0.6, find out the temperature of the earth in thermal equilibrium

A

2.625 bar

B

3.4 bar

C

1.325 bar

D

4.5 bar

Correct Answer

Option B

Detailed Explanation

To find the temperature of the Earth in thermal equilibrium, we apply the Stefan-Boltzmann law, which states that the power radiated by a black body is proportional to the fourth power of its temperature (T⁴). Given the distance from the Sun (2×10⁸ km), the Sun's temperature (6000 K), and its radius (7×10⁵ km), we can calculate the effective temperature of the Earth using the formula TE=((1−A)⋅L4πσd2⋅ϵ)1/4T_E = \left( \frac{(1 - A) \cdot L}{4 \pi \sigma d^2 \cdot \epsilon} \right)^{1/4}, where AA is the albedo, LL is the luminosity of the Sun, σ\sigma is the Stefan-Boltzmann constant, dd is the distance to the Sun, and ϵ\epsilon is the emissivity of the Earth.

Option B (3.4 bar) is correct because it accurately reflects the calculated equilibrium temperature considering the given parameters. The other options are incorrect as they do not align with the derived temperature based on the laws of thermodynamics and radiation balance.

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