STANDARDPhysics-Wave Optics
STANDARD Physics Young's Double Slit Experiment MCQ Question
Type: MCQ-numerical-Medium-Class 12
In a double slit experiment using light of wavelength 600 nm, the angular width of a fringe on a distant screen is 0.1°. The spacing between the two slits is
A
3.44 × 10⁻⁴ m
B
1.54 × 10⁻⁴ m
C
1.54 × 10⁻³ m
D
1.44 × 10⁻³ m
Correct Answer
Option A
Detailed Explanation
The angular width of the fringe is given by θ = λ/d. Rearranging gives d = λ/θ. Substituting the given values, d = (600 × 10⁻⁹ m) / (3.14/1800) = 3.44 × 10⁻⁴ m.
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