STANDARD Physics Young's Double Slit Experiment MCQ Question
In Young's double slit experiment distance between two sources is 0.1 mm. The distance of screen from the source is 20 cm. Wavelength of light used is 5460 Å. Then, angular position of the first dark fringe is
0.08°
0.16°
0.20°
0.31°
Correct Answer
Detailed Explanation
The angular position of the first dark fringe is given by θ₁ = (2n - 1) λ/2d. For the first dark fringe, n = 1. Substituting the given values, θ₁ = (5460 × 10⁻¹⁰ m) / (2 × 0.1 × 10⁻³ m) = 0.16°.
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