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STANDARDPhysics-Current Electricity

STANDARD Physics Resistors in Circuits MCQ Question

Type: MCQ-numerical-Medium-Class 12

If power dissipated in the 9 Ω resistor in the circuit shown is 36 W, the potential difference across the 2 Ω resistor is:

A

4 V

B

8 V

C

10 V

D

2 V

Correct Answer

Option C

Detailed Explanation

The power dissipated in the 9 Ω resistor is given by P = V²/R. Solving for V, we get V = √(P × R) = √(36 × 9) = 18 V. The potential difference across the 2 Ω resistor is calculated using the voltage division rule, resulting in 10 V.

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