STANDARD Physics Drift Velocity MCQ Question
There is a current of 40 amperes in a wire of 10⁻⁶ m² area of cross-section. If the number of free electrons per m³ is 10²⁹, then the drift velocity will be
1.25 × 10⁻³ m/s
2.50 × 10⁻³ m/s
25.0 × 10⁻³ m/s
250 × 10⁻³ m/s
Correct Answer
Detailed Explanation
The drift velocity V can be calculated using the formula V = I / (nqA). Substituting the given values, V = 40 / (10²⁹ × 1.6 × 10⁻¹⁹ × 10⁻⁶) = 2.5 × 10⁻³ m/s.
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