STANDARD Physics Work Done by a Force MCQ Question
A uniform chain of length 2 m is kept on a table such that a length of 60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg. The work done in pulling the entire chain on the table (Take g = 10⁻²)
12.9 J
6.3 J
3.6 J
2.0 J
Correct Answer
Detailed Explanation
The mass of the hanging part of the chain is 1.2 kg, and its weight is 12 N. The center of gravity of the hanging part lies at its midpoint, 0.30 m from the table. The work done is W = 12 × 0.30 = 3.6 J.
Found an issue with this question?
Related Questions
More from Work, Energy and Power
A body of mass 1 kg begins to move under the action of a time dependent force F = (2t î + 3t² ĵ)N, where î and ĵ are unit vectors along x and y ax...
A particle acted upon by constant forces 4î + ĵ − 3k̂ and 3î + ĵ − k̂ is displaced from the point î + 2ĵ + k̂ to point 5î + 4ĵ + k̂. The total...
More from
Which of the following statements about power is correct?
Assertion (A): The work-energy theorem is an integral form of Newton's second law. | Reason (R): The work-energy theorem involves an integral over an ...
Assertion (A): The dot product of two vectors is zero when the vectors are perpendicular. | Reason (R): The scalar product of two vectors is the produ...