STANDARD Physics Kinetic Energy MCQ Question
In a ballistics demonstration a police officer fires a bullet of mass 50 g with speed 200 m s⁻¹ on soft plywood of thickness 2 cm. The bullet emerges with only 10% of its initial kinetic energy. The emergent speed of the bullet is
2√10 ms⁻¹
20√10 ms⁻¹
10√2 ms⁻¹
10√20 ms⁻¹
Correct Answer
Detailed Explanation
The initial kinetic energy of the bullet is 1000 J. Since the bullet emerges with only 10% of its initial kinetic energy, the final kinetic energy is 100 J. Using the formula for kinetic energy, we can solve for the emergent speed, vₑ = √(2Kₑ/m) = 20√10 ms⁻¹.
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