STANDARD Physics Kinetic Energy MCQ Question
The momentum of a body is increased by 25%. The kinetic energy is increased by about
25%
5%
56%
38%
Correct Answer
Detailed Explanation
Kinetic energy of the body is K = p²/2m. When the momentum of a body is increased by 25%, its momentum becomes p' = 1.25p. Therefore, K' = (p')²/2m = (1.25p)²/2m = 1.5625K. The percentage increase in kinetic energy is (K' - K)/K × 100 = 56%.
Found an issue with this question?
Related Questions
More from Work, Energy and Power
A body of mass 1 kg begins to move under the action of a time dependent force F = (2t î + 3t² ĵ)N, where î and ĵ are unit vectors along x and y ax...
A particle acted upon by constant forces 4î + ĵ − 3k̂ and 3î + ĵ − k̂ is displaced from the point î + 2ĵ + k̂ to point 5î + 4ĵ + k̂. The total...
More from
Which of the following statements about power is correct?
Assertion (A): The work-energy theorem is an integral form of Newton's second law. | Reason (R): The work-energy theorem involves an integral over an ...
Assertion (A): The dot product of two vectors is zero when the vectors are perpendicular. | Reason (R): The scalar product of two vectors is the produ...