STANDARD Physics Conservation of Energy MCQ Question
A bullet of mass m moving horizontally with a velocity v strikes a block of wood of mass M and gets embedded in the block. The block is suspended from the ceiling by a massless string. The height to which block rises is
v²/2g (m/(m+M))²
v²/2g (M+m/m)²
v²/2g (m/M)²
v²/2g (M/m)²
Correct Answer
Detailed Explanation
Using the conservation of linear momentum, mv = (m+M)V, where V is the velocity of the block-bullet system just after collision. Using conservation of mechanical energy, 1/2(m+M)V² = (m+M)gh, we find h = V²/2g = v²/2g (m/(m+M))².
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