STANDARD Physics Work done by gases MCQ Question
Under isothermal conditions, a gas at 30 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J]
30 J
−30 J
5 kJ
25 kJ
Correct Answer
Detailed Explanation
Expansion of a gas against a constant external pressure is an irreversible process. The work done in an irreversible process is calculated as −Pₑₓₜ ΔV = −Pₑₓₜ (V₂ − V₁) = −2(0.25 − 0.1) = −2 × 0.15 L bar = −0.30 × 100 J = −30 J.
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