STANDARD Physics Heat Transfer MCQ Question
If 10 g of ice is added to 40 g of water at 15°C, then the temperature of the mixture is (specific heat of water = 4.2 × 10³ J kg⁻¹ K⁻¹, Latent heat of fusion of ice = 3.36 × 10⁵ J kg⁻¹)
15°C
12°C
10°C
0°C
Correct Answer
Detailed Explanation
Heat lost by water to come from 15°C to 0°C is 2520 J. Heat required to convert 10 g ice into 10 g water at 0°C is 3360 J. Since H₂ > H₁, the whole ice will not be converted into water, and the temperature of the whole water will be 0°C. Therefore, the temperature of the mixture is 0°C.
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