STANDARDPhysics-Thermodynamics
STANDARD Physics First Law of Thermodynamics MCQ Question
Type: MCQ-conceptual-Medium-Class 11
A gas is expanded from volume V₀ to 2V₀ under three different processes, as shown in the figure. Process 1 is isobaric process, process 2 is isothermal and process 3 is adiabatic. Let ΔU₁, ΔU₂ and ΔU₃ be the change in internal energy of the gas in these three processes, then
A
U₁ > ΔU₂ > ΔU₃
B
U₁ < ΔU₂ < ΔU₃
C
U₂ < ΔU₁ < ΔU₃
D
U₂ < ΔU₃ < ΔU₁
Correct Answer
Option A
Detailed Explanation
Process 1 is isobaric expansion (P = constant), hence temperature of gas will increase. U₁ is positive. Process 2 is an isothermal process, so ΔU₂ = 0. Process 3 is an adiabatic expansion, hence temperature of gas will fall, making U₃ negative. Therefore, U₁ > ΔU₂ > ΔU₃.
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