STANDARDPhysics-Thermodynamics
STANDARD Physics Thermal Conductivity MCQ Question
Type: MCQ-conceptual-Medium-Class 11
Two bars of same length and same cross-sectional area but of different thermal conductivities, K₁ and K₂ are joined end to end as shown in the figure. One end of the compound bar is at temperature T₁ and the opposite end at temperature T₂ (where T₁ > T₂). The temperature of the junction is
A
K₂T₁ + K₁T₂ / (K₁ + K₂)
B
K₁T₁ + K₂T₁ / (K₁ + K₂)
C
K₂(T₁ + T₂) / K₂
D
K₁(T₁ + T₂) / K₁
Correct Answer
Option A
Detailed Explanation
At steady state, the heat current through both bars is equal. By equating the heat currents and solving for the junction temperature, we find it to be a weighted average of the two temperatures based on their conductivities.
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