STANDARD Physics Spring-Mass Systems MCQ Question
When a mass m is connected individually to two springs S₁ and S₂, the oscillation frequencies are v₁ and v₂. If the same mass is attached to the two springs as shown in figure, the oscillation frequency would be
v₁ + v₂
√(v₁² + v₂²)
(1/v₁ + 1/v₂)⁻¹
√(v₁² - v₂²)
Correct Answer
Detailed Explanation
When two springs are in series, the effective spring constant k is given by 1/k = 1/k₁ + 1/k₂. The frequency of oscillation is determined by the effective spring constant and the mass. Therefore, the frequency is given by (1/v₁ + 1/v₂)⁻¹.
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