STANDARD Physics Simple Harmonic Motion MCQ Question
Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated on the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is
x(t) = Bcos(π/15 t)
x(t) = Bsin(π/15 t + π/2)
x(t) = Bcos(π/15 t + π/2)
x(t) = Bsin(2πt/30)
Correct Answer
Detailed Explanation
The projection of the circular motion on the x-axis is a simple harmonic motion. Given the period T = 30 s, the angular frequency ω = 2π/T = 2π/30. Thus, the x-projection is x(t) = Bsin(ωt) = Bsin(2πt/30).
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