STANDARD Physics Simple Harmonic Motion MCQ Question
Starting from the origin, a body oscillates simple harmonically with a period of 2s. After what time will its kinetic energy be 75% of the total energy?
1/6 s
1/4 s
1/3 s
1/12 s
Correct Answer
Detailed Explanation
The kinetic energy (KE) is 75% of the total energy (E), so KE = 0.75E. Using the relation KE = 0.5mω²x² and the given condition, we find that cos²(ωt) = 3/4. Solving for ωt gives ωt = π/6, and since ω = π, t = 1/6 s.
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