STANDARDPhysics-Oscillations
STANDARD Physics Simple Harmonic Motion MCQ Question
Type: MCQ-conceptual-Medium-Class 11
A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be
A
β²/α
B
2π√(α)/α
C
β²/α²
D
α/β
Correct Answer
Option B
Detailed Explanation
Using the relationships α = ω²A and β = ωA, we find the time period T = 2π/ω = 2πβ/α.
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