STANDARD Physics Simple Harmonic Motion MCQ Question
A particle executing SHM according to the equation x = 5cos(2πt + π/4) in SI units. The displacement and acceleration of the particle at t = 1.5 s is
−3.0 m, 100 m s⁻²
+2.54 m, 200 m s⁻²
−3.54 m, 140 m s⁻²
+3.55 m, 120 m s⁻²
Correct Answer
Detailed Explanation
At t = 1.5 s, the displacement x = 5cos(3π + π/4) = −3.54 m. The acceleration a = −ω²x = −(2π)²(−3.54) = 140 m s⁻².
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