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STANDARD Physics Simple Harmonic Motion MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The x-t graph of a particle undergoing simple harmonic motion is as shown in the figure. The acceleration of the particle at t = 4/3 s is

A

√3/32 π² cm s⁻²

B

-π²/32 cm s⁻²

C

π²/32 cm s⁻²

D

√3/32 π² cm s⁻²

Correct Answer

Option A

Detailed Explanation

From the graph, the amplitude A = 1 cm and the period T = 8 s. At t = 4/3 s, the displacement x = 1 sin(2π/8 * 4/3) = √3/2 cm. In SHM, acceleration a = -ω²x, where ω = 2π/T. Calculating gives a = √3/32 π² cm s⁻².

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