STANDARD Physics Simple Harmonic Motion MCQ Question
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration.
8π/3
4π/3
3π/8
7π/3
Correct Answer
Detailed Explanation
In SHM, the speed v = ω√(A² - x²) and acceleration a = -ω²x. Given |v| = |a|, we solve for ω and find the period T = 2π/ω = 8π/3.
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