STANDARD Physics Simple Harmonic Motion MCQ Question
A simple harmonic motion is represented by y = 5(sin3πt + √3 cos3πt) cm. The amplitude and time period of the motion are
5 cm, 3/2 s
10 cm, 2/3 s
5 cm, 2/3 s
10 cm, 3/2 s
Correct Answer
Detailed Explanation
The given equation can be rewritten as y = 10 sin(3πt + π/3), indicating an amplitude A = 10 cm. The angular frequency ω = 3π, so the time period T = 2π/ω = 2/3 s.
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