STANDARD Physics Simple Harmonic Motion MCQ Question
A body of mass 20 g connected to a spring of spring constant k, executes simple harmonic motion with a frequency of (5/π) Hz. The value of spring constant is
4 N m⁻¹
3 N m⁻¹
2 N m⁻¹
5 N m⁻¹
Correct Answer
Detailed Explanation
The frequency of simple harmonic motion is given by f = (1/2π)√(k/m). Given f = 5/π Hz and m = 20 g = 0.02 kg, solving for k gives k = 2 N m⁻¹.
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