STANDARD Physics Simple Harmonic Motion MCQ Question
A trolley of mass 3 kg, as shown in figure, is connected to two identical springs, each of spring constant 600 N m⁻¹. If the trolley is displaced from its equilibrium position by 5 cm and released, the maximum speed of the trolley is
0.5 m s⁻¹
1 m s⁻¹
2 m s⁻¹
3 m s⁻¹
Correct Answer
Detailed Explanation
In the given figure, two identical springs are connected in parallel. The effective spring constant is k_eff = 2k = 2 × 600 N m⁻¹ = 1200 N m⁻¹. Here, Amplitude, A = 5 cm = 0.05 m, m = 3 kg. Angular frequency of oscillation ω = √(k_eff/m) = √(1200 N m⁻¹/3 kg) = 20 s⁻¹. Maximum speed, v_max = Aω = (0.05 m) (20 s⁻¹) = 1 m s⁻¹.
Found an issue with this question?
Related Questions
More from
Assertion (A): The acceleration in simple harmonic motion is always directed towards the mean position. | Reason (R): In simple harmonic motion, accel...
Consider a block attached to a spring on a frictionless surface, as described in the context. If the displacement of the block from the wall is given ...
What is the relationship between the driving frequency and the amplitude of an oscillator in Simple Harmonic Motion?