STANDARDPhysics-Motion in a Plane
STANDARD Physics Projectile Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
In the previous question the speed with which the stone hits the ground is
A
15 m s⁻¹
B
90 m s⁻¹
C
99 m s⁻¹
D
49 m s⁻¹
Correct Answer
Option C
Detailed Explanation
The speed of the stone when it hits the ground is calculated using v = √(vₓ² + vᵧ²). Here, vₓ = 15 m s⁻¹ and vᵧ = 98 m s⁻¹. Therefore, v = √(15² + 98²) ≈ 99 m s⁻¹.
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