STANDARDPhysics-Motion in a Plane
STANDARD Physics Projectile Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with a speed of 15 m s⁻¹. The time taken by the stone to reach the ground is
A
5 s
B
10 s
C
12 s
D
15 s
Correct Answer
Option B
Detailed Explanation
The time taken by the stone to reach the ground is calculated using the formula t = √(2h/g). Substituting h = 490 m and g = 9.8 m s⁻², we get t = √(2×490/9.8) = 10 s.
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