STANDARDPhysics-Laws of Motion
STANDARD Physics Pulley Systems MCQ Question
Type: MCQ-numerical-Medium-Class 11
Two masses m₁ = 1 kg and m₂ = 2 kg are connected by a light inextensible string and suspended by means of a weightless pulley as shown in the figure. Assuming that both the masses start from rest, the distance travelled by the centre of mass in two seconds is (Take g = 10 m s⁻²)
A
20/9 m
B
40/9 m
C
2/3 m
D
1/3 m
Correct Answer
Option A
Detailed Explanation
The acceleration of the system is calculated using the formula a = (m₂ - m₁)g / (m₁ + m₂). Substituting the given values, a = (2 - 1)g / (1 + 2) = g/3. The acceleration of the centre of mass is a_CM = (m₁a₁ + m₂a₂) / (m₁ + m₂) = g/9. The distance travelled by the centre of mass in two seconds is s = 1/2 a_CM t² = 20/9 m.
Found an issue with this question?