STANDARD Physics Friction MCQ Question
A block of mass 10 kg is placed on rough horizontal surface whose coefficient of friction is 0.5. If a horizontal force of 100 N is applied on it, then acceleration of the block will be [Take g = 10 m s⁻²]
10 m s⁻²
5 m s⁻²
15 m s⁻²
0.5 m s⁻²
Correct Answer
Detailed Explanation
The force of friction is calculated as f = μmg = 0.5 × 10 kg × 10 m s⁻² = 50 N. The net force causing acceleration is F' = F - f = 100 N - 50 N = 50 N. Thus, acceleration a = F'/m = 50 N / 10 kg = 5 m s⁻².
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