STANDARD Physics Friction MCQ Question
The coefficient of static friction between the box and the train's floor is 0.2. The maximum acceleration of the train in which a box lying on its floor will remain stationary is (Take g = 10 m s⁻²)
2 m s⁻²
4 m s⁻²
6 m s⁻²
8 m s⁻²
Correct Answer
Detailed Explanation
As acceleration of the box is due to static friction, ma ≤ fₛ ≤ μₛmg. Therefore, aₘₐₓ = μₛg = 0.2 × 10 m s⁻² = 2 m s⁻².
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