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STANDARD Physics Potential Energy MCQ Question

Type: MCQ-conceptual-Medium-Class 11

In the previous question, the potential at the centre is

$-\frac{2Gm}{l}$

$-\frac{3\sqrt{2}Gm}{l}$

$-\frac{2\sqrt{2}Gm}{l}$

$-\frac{4\sqrt{2}Gm}{l}$

Correct Answer

Option D

Detailed Explanation

The potential at the center due to the mass configuration is calculated by summing the potentials due to each mass. Using symmetry and the given configuration, the potential is - $\frac$ {4 $\sqrt$ {2}Gm}{l}.

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