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STANDARD Physics Gravitational Potential Energy MCQ Question

Type: MCQ-numerical-Medium-Class 11

Four particles each of mass m are placed at the vertices of a square of side l. The potential energy of the system is

Question diagram
A

−2Gm2l(2−12)-\frac{\sqrt{2}Gm^2}{l} \left(2 - \frac{1}{\sqrt{2}}\right)

B

−2Gm2l(2+12)-\frac{2Gm^2}{l} \left(2 + \frac{1}{\sqrt{2}}\right)

C

−2Gm2l(2+12)-\frac{\sqrt{2}Gm^2}{l} \left(\sqrt{2} + \frac{1}{\sqrt{2}}\right)

D

−2Gm2l(2−12)-\frac{2Gm^2}{l} \left(\sqrt{2} - \frac{1}{\sqrt{2}}\right)

Correct Answer

Option B

Detailed Explanation

The potential energy of the system is calculated by summing the potential energy between each pair of particles. For a square, this involves calculating the potential energy for side lengths and diagonals, leading to the given expression.

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