STANDARD Physics Average Velocity and Acceleration MCQ Question
A particle is moving on a circular path of radius R with constant speed v. During motion off the particle from point A to point B
Average speed is v/2
The magnitude of average velocity is v/π
The magnitude of average acceleration is 2v²/πR
Average velocity is zero
Correct Answer
Detailed Explanation
The average acceleration is calculated as the change in velocity divided by the time taken. Since the particle is moving in a circular path, the change in velocity is 2v (from v to -v), and the time taken is πR/v. Thus, the average acceleration is 2v²/πR.
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