STANDARD Chemistry Colligative Properties MCQ Question
We have three aqueous solutions of NaCl labelled as 'A', 'B' and 'C' with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van't Hoff factor for these solutions will be in the order
iₐ < i_b < i_c
iₐ > i_b > i_c
iₐ = i_b = i_c
iₐ < i_b > i_c
Correct Answer
Detailed Explanation
As NaCl is a strong electrolyte, it undergoes dissociation completely. Thus, van't Hoff factor will be same for all these solutions, iₐ = i_b = i_c.
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