STANDARDChemistry-Solutions
STANDARD Chemistry Colligative Properties MCQ Question
Type: MCQ-numerical-Medium-Class 12
The elevation in boiling point of a solution of 9.43 g of MgCl₂ in 1 kg of water is (K_b = 0.52 K kg mol⁻¹, Molar mass of MgCl₂ = 94.3 g mol⁻¹)
A
0.156
B
0.52
C
0.17
D
0.94
Correct Answer
Option A
Detailed Explanation
MgCl₂ dissociates into Mg²⁺ and 2Cl⁻ ions, giving i = 3. The elevation in boiling point (ΔT_b) is calculated using ΔT_b = iK_bm, where m is the molality. Substituting the values, ΔT_b = 3 × 0.52 × (9.43 / 94.3) = 0.156 K.
Found an issue with this question?