STANDARD Chemistry Molar Conductivity MCQ Question
Molar conductivity of 0.15 M solution of KCl at 298 K, if its conductivity is 0.0152 S cm⁻¹, will be
124 Ω⁻¹ cm² mol⁻¹
204 Ω⁻¹ cm² mol⁻¹
101 Ω⁻¹ cm² mol⁻¹
300 Ω⁻¹ cm² mol⁻¹
Correct Answer
Detailed Explanation
Molar conductivity (Λₘ) is calculated using the formula Λₘ = κ × 1000 / M, where κ is the conductivity and M is the molarity. Substituting the given values, Λₘ = 0.0152 × 1000 / 0.15 = 101 Ω⁻¹ cm² mol⁻¹.
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