STANDARD Chemistry Gibbs Free Energy MCQ Question
G° for the reaction, Cu²⁺ + Fe → Fe²⁺ + Cu is (Given : E°{Cu²⁺/Cu} = +0.34 V, E°{Fe²⁺/Fe} = -0.44 V)
11.44 kJ
180.8 kJ
150.5 kJ
28.5 kJ
Correct Answer
Detailed Explanation
The Gibbs free energy change (G°) can be calculated using the formula G° = -nFE°cell. Substituting the given values, G° = 150.5 kJ.
Found an issue with this question?
Related Questions
More from Electrochemistry
E° value of Ni²⁺/Ni is^{-0}.25 V and Ag⁺/Ag is +0.80 V. If a cell is made by taking the two electrodes what is the feasibility of the reaction?
The molar conductivity of 0.007 M acetic acid is 20 S cm² mol⁻¹. What is the dissociation constant of acetic acid? Choose the correct option. [Λ°_H⁺ =...
An electric charge of 5 Faradays is passed through three electrolytes AgNO₃, CuSO₄ and FeCl₃ solution. The grams of each metal liberated at cathode wi...
More from
Calculate the dissociation constant \( K_a \) for acetic acid given that its conductivity is \( 4.95 \times 10^{-5} \text{ S cm}^{-1} \) at a concentr...
Match Column-I with Column-II. Column-I Column-II (a) Cathode reaction (i) Cu 2+ (aq) + 2e – → Cu (s) (b) Anode reaction (ii) Cu(s) ...