STANDARDChemistry-Thermodynamics
STANDARD Chemistry Entropy and Free Energy MCQ Question
Type: MCQ-numerical-Medium-Class 11
A reaction is at equilibrium at 100°C and the enthalpy change for the reaction is 42.6 kJ mol⁻¹. What will be the value of ΔS in J K⁻¹ mol⁻¹?
A
120
B
426.2
C
373.1
D
114.2
Correct Answer
Option D
Detailed Explanation
At equilibrium, ΔG = 0, so ΔH = TΔS. Rearranging gives ΔS = ΔH/T. Substituting the given values, ΔS = 42600 J mol⁻¹ / 373 K = 114.2 J K⁻¹ mol⁻¹.
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