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RE-NEET 2026 Physics Refraction and Apparent Depth MCQ Question

Type: MCQ-diagram based-Medium-Class 12

Consider three media P, Q and R with refractive indices 1, 1.25, and 1.5, respectively. The medium Q having a thickness of 5 cm is placed between extended media P and R as shown in the figure. An object O is placed at the center of medium Q. If viewed from medium P near the normal direction, the apparent depth of O is h₁. For similar observation from medium R, the apparent depth is h₂. The value of |h₁−h₂|, in cm, is:

Question diagram
A

1

B

3

C

2

D

0

Correct Answer

Option A

Detailed Explanation

Apparent depth seen from a medium of index nobsn_{obs}, for an object sitting in a medium of index nmedn_{med}, is

h′=h nobsnmedh' = h\,\frac{n_{obs}}{n_{med}}

The object is at the centre of Q, so h=2.5h = 2.5 cm from either face.

Viewed from P: h1=2.5×11.25=2h_1 = 2.5 \times \frac{1}{1.25} = 2 cm. Viewed from R: h2=2.5×1.51.25=3h_2 = 2.5 \times \frac{1.5}{1.25} = 3 cm.

∣h1−h2∣=1 cm|h_1 - h_2| = 1\ \text{cm}

Answers of 2 or 3 come from quoting one apparent depth instead of the difference; 0 comes from assuming the two views must agree, which they only would if P and R had the same refractive index.

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