RE-NEET 2026 Physics Inductors in Circuits MCQ Question

The emf is measured between a and b, so what matters is which coils lie between those two points.

In P the two inductors are in series and a, b straddle only the first one, which carries the whole current:

$E_P = L\frac{dI}{dt}$

In Q the two inductors are in parallel and a, b straddle the pair. Identical coils split the current equally, so each carries $I/2$:

$E_Q = L\frac{d(I/2)}{dt} = \frac{L}{2}\frac{dI}{dt}$

$\frac{E_P}{E_Q} = 2$

A ratio of 4 comes from taking a, b across both series coils; $\frac{1}{2}$ and $\frac{1}{4}$ invert the comparison.