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RE-NEET2026Physics-Mechanics

RE-NEET 2026 Physics Collisions MCQ Question

Type: MCQ-numerical-Hard-Class 11

Bob B of mass m at rest is hanging vertically from the ceiling via a massless string of length 10 m, as shown in the figure. Point mass A of mass m travelling horizontally with speed 10 ms⁻¹ hits bob B elastically. The bob B rises h meter after the collision. Taking the acceleration due to gravity g = 10 ms⁻² and neglecting the size of the bob, the value of h is:

Question diagram
A

7

B

5

C

2.5

D

8

Correct Answer

Option B

Detailed Explanation

✅ Ans: 2.5 m

Key Concept: First find the velocity of bob B after collision, then apply K.E. → P.E.

12mvB2=mgh\frac12 mv_B^2=mgh h=vB22g=2.5 m\boxed{h=\frac{v_B^2}{2g}=2.5\,m}

❌ Why other options are wrong?

  • 7 m ❌ → incorrect post-collision velocity used
  • 5 m ❌ → assumes vB=10 m/sv_B=10\,m/s after collision
  • 8 m ❌ → incorrect energy conversion

📌 NCERT: “In an isolated system, total momentum remains conserved.”

🧠 NEET Trap: Collision first → find velocity → then use K.E. = P.E.

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