Zoology-Natural Selection
NEET Zoology Natural Selection MCQ Question
Type: MCQ-numerical-Easy-Class 12
If in a population, the frequency of allele A is 0.6, what would be the expected frequency of heterozygous individuals (Aa) according to the Hardy-Weinberg principle?
A
0.24
B
0.36
C
0.48
D
0.16
Correct Answer
Option C
Detailed Explanation
Using the Hardy-Weinberg principle, the frequency of Aa individuals is calculated as 2pq. Given p = 0.6, q = 1 - 0.6 = 0.4, the frequency of Aa is 2 * 0.6 * 0.4 = 0.48.
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