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Zoology-Hardy-Weinberg Principle

NEET Zoology Hardy-Weinberg Principle MCQ Question

Type: MCQ-numerical-Easy-Class 12

In a population of 1000 individuals, if the frequency of allele A (p) is 0.7, what is the expected number of heterozygous individuals (Aa) according to the Hardy-Weinberg principle?

A

420

B

490

C

210

D

140

Correct Answer

Option B

Detailed Explanation

The Hardy-Weinberg principle states that the frequency of Aa individuals is 2pq. With p = 0.7 and q = 0.3, 2pq = 2(0.7)(0.3) = 0.42. Thus, 0.42 * 1000 = 420 heterozygous individuals.

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