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Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-numerical-Medium-Class 12

If a semiconductor has an intrinsic carrier concentration nin_i of 1.5×1010 m−31.5 \times 10^{10} \text{ m}^{-3} and the electron concentration nen_e in an n-type semiconductor is 5×1022 m−35 \times 10^{22} \text{ m}^{-3}, what is the hole concentration nhn_h in the same semiconductor?

A

5×109 m−35 \times 10^9 \text{ m}^{-3}

B

3×1012 m−33 \times 10^{12} \text{ m}^{-3}

C

5×1010 m−35 \times 10^{10} \text{ m}^{-3}

D

7.5×1020 m−37.5 \times 10^{20} \text{ m}^{-3}

Correct Answer

Option A

Detailed Explanation

Using the relation nenh=ni2n_e n_h = n_i^2, and substituting ni=1.5×1010 m−3n_i = 1.5 \times 10^{10} \text{ m}^{-3} and ne=5×1022 m−3n_e = 5 \times 10^{22} \text{ m}^{-3}, we find nh=(1.5×1010)25×1022=4.5×109 m−3n_h = \frac{(1.5 \times 10^{10})^2}{5 \times 10^{22}} = 4.5 \times 10^9 \text{ m}^{-3}.

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