Physics-Nuclear Fission
NEET Physics Nuclear Fission MCQ Question
Type: MCQ-numerical-Easy-Class 12
What is the total energy released in MeV when 2 kg of pure 239 94 Pu undergoes fission?
A
81 x 10^25 MeV
B
50 x 10^25 MeV
C
01 x 10^25 MeV
D
62 x 10^25 MeV
Correct Answer
Option A
Detailed Explanation
The energy released per fission of 239 94 Pu is 180 MeV. Using Avogadro's number and the molar mass of Pu, the total number of fissions can be calculated, leading to a total energy release of 1.81 x 10^25 MeV.
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