Physics-Nuclear Fission
NEET Physics Nuclear Fission MCQ Question
Type: MCQ-numerical-Easy-Class 12
How much energy, in MeV, is released if 2 kg of pure 239 Pu undergo fission, given that the average energy released per fission is 180 MeV?
A
7.5 × 10^23 MeV
B
2 × 10^25 MeV
C
5 × 10^24 MeV
D
6 × 10^24 MeV
Correct Answer
Option B
Detailed Explanation
The number of atoms in 2 kg of Pu is calculated using Avogadro's number and the molar mass, leading to a total energy release of approximately 1.2 × 10^25 MeV.
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