NEET Physics Magnetic Force on Current MCQ Question
A straight wire carrying a current of 12 A is bent into a semi-circular arc of radius 2.0 cm. If the magnetic field at the center of the arc is due to the semicircular part only, what would be the magnitude of this magnetic field at the center?
1.2 × 10^-4 T
3.8 × 10^-4 T
6.0 × 10^-4 T
9.0 × 10^-4 T
Correct Answer
Detailed Explanation
Using the Biot-Savart law for a semicircular wire, B = (μ₀I)/(4R). Substituting I = 12 A and R = 0.02 m, we get B = 1.2 × 10^-4 T.
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