Physics-Biot-Savart Law
NEET Physics Biot-Savart Law MCQ Question
Type: MCQ-numerical-Easy-Class 12
Using the Biot-Savart Law, calculate the magnetic field at a point due to a current element of length 2 cm carrying a current of 10 A, located at a perpendicular distance of 0.5 m from the point.
A
4 × 10^-8 T
B
8 × 10^-8 T
C
2 × 10^-8 T
D
10 × 10^-8 T
Correct Answer
Option A
Detailed Explanation
The magnetic field is calculated using B = (μ₀/4π) * (2 I l sin θ / r²). Given μ₀/4π = 10^-7 T m/A, I = 10 A, l = 0.02 m, r = 0.5 m, and sin θ = 1, B = 4 × 10^-8 T.
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