Physics-Biot-Savart Law
NEET Physics Biot-Savart Law MCQ Question
Type: MCQ-numerical-Easy-Class 12
Given a long straight wire carrying a current of 10 A, at a distance of 0.5 m from the wire, what is the magnitude of the magnetic field produced?
A
4 × 10^-8 T
B
2 × 10^-7 T
C
1 × 10^-6 T
D
3 × 10^-7 T
Correct Answer
Option A
Detailed Explanation
Using the Biot-Savart Law with given values: B = (μ0/4π) × (2I/r) = 4 × 10^-8 T, as shown in the NCERT example.
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