NEET Physics Magnetic Properties of Materials MCQ Question
A ferromagnetic material with a domain volume of 10^(-18) m^3 and a density of 7.9 g/cm^3 is fully magnetized. If each iron atom has a dipole moment of 9.27 × 10^(-24) A m^2, what is the maximum possible magnetisation M_max of the material?
8.0 × 10^5 A/m
7.9 × 10^5 A/m
9.0 × 10^5 A/m
8.5 × 10^5 A/m
Correct Answer
Detailed Explanation
The maximum magnetisation M_max is calculated by dividing the total dipole moment by the domain volume: M_max = (8.65 × 10^10 atoms) × (9.27 × 10^(-24) A m^2)/10^(-18) m^3 = 8.0 × 10^5 A/m.
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