Physics-Earth's Magnetism
NEET Physics Earth's Magnetism MCQ Question
Type: MCQ-numerical-Hard-Class 12
The horizontal component of the Earth's magnetic field is required at a location where the total magnetic field strength is 0.39 G and the angle of dip is 35°. What is the horizontal component of the magnetic field?
A
0.32 G
B
0.39 G
C
0.23 G
D
0.47 G
Correct Answer
Option A
Detailed Explanation
The horizontal component of the Earth's magnetic field is calculated using B_horizontal = B_total * cos(dip angle). Here, B_horizontal = 0.39 G * cos(35°) ≈ 0.32 G.
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